Question

2^(x+3)=5^x

Help solve for x

Answer 1

can someone show me the steps

Answer 2

@zepdrix pls, i dont get it!

Answer 3

Try take log of both sides.

Answer 4

Like \(\ln(2^{x+3})=\ln(5^x)\).

Then you can use this logarithm property \(\log(a^b) = b\log(a)\)

Answer 5

HI!!

Answer 6

it is a raft of algebra after the first step

Answer 7

\[2^{x+3}=5^x\] first step is
\[(x+3)\ln(2)=x\ln(5)\] then solve for \(x\)
actually not too much algebra in this one

Answer 8

distribute and get

\[\ln(2)x+3\ln(2)=x\ln(5)\] put all the \(x\) terms on the right and get
\[3\ln(2)=\ln(5)x-\ln(2)x\] then factor out the \(x\)
\[3\ln(2)=(\ln(5)-\ln(2))x\] and finally divide