Question

Would the equation 3x^2+x-5=0 have two complex roots?

Answer 1

Factor out 3x^2-x-5
(3x+5)(x-2)
Set each equal to 0
3x+5=0
x-2=0
solve
X=-5/3 and x=2

Answer 2

no the value of \[b^2-4ac>0\] .
hence no complex roots...it will have two distinct real roots

Answer 3

Could you show me how you got that. I guess I just don't understand it very well. Please :)

Answer 4

it is actually kinda formula.
\[\Delta=b^2-4ac \] it is called the discriminant
if \[\Delta>0 ( we \space have \space two \space real \space distinct \space roots)\]
\[\Delta=0 ( we \space have \space two \space real \space but \space equal \space roots)\]
\[\Delta<0 ( we \space have \space two \space complex \space roots)\]

Answer 5

@answers4you

Factor out 3x^2-x-5
(3x+5)(x-2) = 3x^2-x -10 therefore not a correct factorisation