What is the sum 1/g+2 +3/g+1
a. 3/g+3
b. g+3/(g+1)(g+2)
c. 4g+7/(g+1)(g+2)
d. 2g+3/(g+1)(g+2)
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OpenStudy (phi):
what common denominator can you use ?
OpenStudy (anonymous):
g+3?
OpenStudy (phi):
no, the common denominator is not g+3
I would multiply the two denominators to get a common denominator
OpenStudy (phi):
notice most of your answer choices do that
OpenStudy (anonymous):
ok so its (g+1)(g+2)
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OpenStudy (phi):
yes. next, what do you multiply the first fraction by so you get that denominator ?
remember you multiply top and bottom by the same thing
OpenStudy (anonymous):
(1)(g+1)?
OpenStudy (phi):
yes, and you do that in the bottom also so that you get
\[ \frac{g+1}{(g+1)(g+2) }\]
OpenStudy (phi):
now what about the second fraction?
OpenStudy (anonymous):
(3)(g+2)=3g+2?
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OpenStudy (phi):
close. you have 3 "packages" of (g+2)
which means you have 3 of everything inside the package
in other words, redo this part :3(g+2) becuase it's not 3g+2.
OpenStudy (anonymous):
ok
OpenStudy (phi):
do you get the idea? 3(g+2) means the same as (g+2)+(g+2) + (g+2)
how many g's is that ? how many 2's ?
OpenStudy (anonymous):
3 gs and 3 2s
OpenStudy (phi):
and you can write that as
3g+3*2
or 3g+2+2+2
but most people would write it
3g+6
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OpenStudy (anonymous):
ok
OpenStudy (phi):
now both fractions have the same denominator.
you can add their "tops"