Question

PLEASE HELP!!! Suppose you make 90% of your free throws and you attempt 3 free throws. Use the bionomial theorem to calculate each probability.
a.) you don't make any of them
b.) you make 1
c.) you make 2
d.) you make all 3

Answer 1

whats the thrm tell us?

Answer 2

P(x)= vnC vx P^xq^n-x

Answer 3

but I don't understand how to find C?

Answer 4

C is a notation for combinatorics

Answer 5

n C r means:\[\frac{n!}{r!(n-r)!}\]

Answer 6

another way of look at it is:

(p+q)^n ; such that p+q = 1

\[(.90 + .10)^3 = 1(.90)^3(.10)^0+ 3(.90)^2(.10)^1 + 3(.90)^1(.10)^2+ 1(.90)^0(.10)^3\]

its a binomial cumulative distribution function

Answer 7

thank you so much! can you just show me what the equation would look like for A? I should be able to solve it i'm just having trouble writing the equation out.

Answer 8

\[ \underbrace{1(.90)^3(.10)^0}_{P(3)}+ \underbrace{3(.90)^2(.10)^1}_{P(2)} + \underbrace {3(.90)^1(.10)^2}_{P(1)}+ \underbrace{1(.90)^0(.10)^3}_{P(0)}\]

Answer 9

the nCr is the coefficients of a pascal triangle, ^3 = 1 3 3 1

\[\binom{3}{0}=3C0=1\]
\[\binom{3}{1}=3C1=3\]
\[\binom{3}{2}=3C2=3\]
\[\binom{3}{3}=3C3=1\]

Answer 10

P(0) is the probability that we make none of them ....

Answer 11

thank you SOO much!!

Answer 12

youre welcome