Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

What is the equation of the graphed linear model? y = ___ x +___ http://static.k12.com/calms_media/media/1549000_1549500/1549109/2/a4d8cb5972366f402912ed1759aeadaa5560d1f1/MS_IMC-141014-181213.jpg

OpenStudy (anonymous):

@Preetha can you help me??

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

hia again

OpenStudy (amistre64):

whats our slope? and hi

OpenStudy (anonymous):

idk yet because idk what numbers to use

OpenStudy (anonymous):

y=mx+b

OpenStudy (amistre64):

the line goes thru 2 readily seen points. use them

OpenStudy (amistre64):

what are the points?

OpenStudy (anonymous):

oh (1,3) and (10,11)

OpenStudy (amistre64):

9,11 but yeah

OpenStudy (anonymous):

oh ya lol

OpenStudy (anonymous):

so i have to do Y1 - Y2 ------ X1 - X2

OpenStudy (amistre64):

you prolly could yeah :)

OpenStudy (anonymous):

is the slope 1

OpenStudy (amistre64):

yep, and when x=0 what would you gander the y intercept is from the chart?

OpenStudy (anonymous):

uh 0 i think so b= 0

OpenStudy (anonymous):

so y=mx+b = y= 1 x + b

OpenStudy (anonymous):

y=1x+0

OpenStudy (amistre64):

the line is not crossing the y axis anywhere near y=0 ... we can do this the hard way if you want .. given a point (a,b) and a slope, m: we can construct the "point-slope" form if a line as: y-b = m(x-a) and then conform it to your particular setup as y = mx -ma + b keeping in mind that this b is not your b

OpenStudy (amistre64):

or we could just adjust it by the point 1,3 is on the line sooo y = mx + b 3 = 1(1) + b ; what is b?

OpenStudy (anonymous):

i think 1

OpenStudy (anonymous):

I forgot how to find the y-intercept

OpenStudy (amistre64):

3 = 1 + 1 ... not quite right

OpenStudy (anonymous):

oh 2 lol

OpenStudy (anonymous):

maybe

OpenStudy (amistre64):

you find the y intercept (the point it cross the y axis) by looking at the chart or filling in the values

OpenStudy (amistre64):

3 = 1 + b, so b = 2 yes there are many ways to approach this.

OpenStudy (anonymous):

ya i feel dumb

OpenStudy (anonymous):

thank you again theirs your medal

OpenStudy (amistre64):

good luck :)

OpenStudy (anonymous):

do you think you can help me with this one or check it

OpenStudy (amistre64):

maybe

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Based on the linear model, what is the possible value of Variable K when Variable J is 2? http://static.k12.com/calms_media/media/1549000_1549500/1549111/1/2645d5608dd2447fe0a945a17ea65ea92e58e6cb/MS_IMC-141014-181215.jpg

OpenStudy (amistre64):

and your solution would be what?

OpenStudy (anonymous):

i got 27

OpenStudy (anonymous):

is that right??

OpenStudy (amistre64):

i dont see how you would even get that find j=2, follow it up till you hit the line, then move left to find its k value |dw:1429907341319:dw|

OpenStudy (amistre64):

what is the value of k at the point?

OpenStudy (anonymous):

k=j+2

OpenStudy (anonymous):

oh is it j=k+2

OpenStudy (amistre64):

no, it exactly like i instructed you to do ...

OpenStudy (anonymous):

02

OpenStudy (anonymous):

20

OpenStudy (amistre64):

yeah ... its 20

OpenStudy (anonymous):

2,20

OpenStudy (anonymous):

nvm its just 20 right

OpenStudy (amistre64):

when j=2, the line suggests k=20

OpenStudy (anonymous):

so the answer is 20 correct

OpenStudy (amistre64):

yeah ... its 20, again

OpenStudy (anonymous):

ok thank again ^_^ i wish i can give you 100 metals thx

OpenStudy (amistre64):

goodluck ...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!