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Physics 21 Online
OpenStudy (kkbrookly):

Help please!

OpenStudy (kkbrookly):

A 45 V battery is connected to a 10.0 Ω resistor and a 5.0 Ω resistor in series. What will be the total current in the circuit?

OpenStudy (kkbrookly):

0.33 A 3.0 A 4.5 A 9.0 A

OpenStudy (anonymous):

using I = V/R (Ohm's Law) V = 45 R = 15 I = 45/15 I = 3/1 I = 3.0 A So I believe the second 3.0A answer is correct. (I believe when resistors are connected in parallel they can just be added together)

OpenStudy (kkbrookly):

Thank you! What about this one? If you have a 45.0 V battery connected to a 10.0 Ω resistor and a 5.00 Ω resistor in series, what will be the total power output in the circuit? 45.0 W 135 W 203 W 405 W

OpenStudy (kkbrookly):

@YoungElk

OpenStudy (kkbrookly):

Nevermind I figured it out! Thank you!

OpenStudy (anonymous):

From the last question we found that the amperage (A) = 3.0, We are told that the voltage (V) = 45.0 To calculate Wattage (W) you need to times Voltage (V) by Amperage (A) so W = AV W = 3 * 45 W = 135 W so the second answer

OpenStudy (kkbrookly):

That's what I got as well

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