Mathematics
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OpenStudy (darkbluechocobo):
Help with vectors
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OpenStudy (darkbluechocobo):
Which of the following is a vector that has a direction angle of θ = 67° and a magnitude of 3/7 Round your answer to the nearest tenth.
OpenStudy (darkbluechocobo):
(0.2,-0.4)
(0.4, 0.2)
(- 0.4 0.2)
( 0.2, 0.4)
OpenStudy (darkbluechocobo):
I am having issues finding the magnitude because 3/7= .428 and (.2)^2+(-.4)^2=.447
OpenStudy (darkbluechocobo):
so basically they all have the same magnitude
OpenStudy (darkbluechocobo):
oh wait
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jimthompson5910 (jim_thompson5910):
|dw:1429925115014:dw|
jimthompson5910 (jim_thompson5910):
|dw:1429925124779:dw|
OpenStudy (darkbluechocobo):
the formula to get this is ||v||cosTheta and our theta is 67
jimthompson5910 (jim_thompson5910):
|dw:1429925158047:dw|
OpenStudy (darkbluechocobo):
I'm really confused by that :/ do you solve for both y and x?
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jimthompson5910 (jim_thompson5910):
each vector is <x,y>
divide each answer choice, the coordinates y over x and see which are equal to tan(67)
tan(67) is approximately equal to 2.355852
jimthompson5910 (jim_thompson5910):
also, keep in mind that the vector is in quadrant 1 as shown above
OpenStudy (darkbluechocobo):
with what you said means that both of them are positive
geerky42 (geerky42):
Yes.
OpenStudy (darkbluechocobo):
well it would be .4/.2
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OpenStudy (darkbluechocobo):
it gives you exactly 2 though s:
jimthompson5910 (jim_thompson5910):
yes that's the closest we get
jimthompson5910 (jim_thompson5910):
there is roundoff error
OpenStudy (darkbluechocobo):
Ah i see
OpenStudy (darkbluechocobo):
Thank you
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jimthompson5910 (jim_thompson5910):
np