One hundred pennies are being distributed independently and at random into 30 boxes, labeled 1, 2, ..., 30. What is the probability that there are exactly 3 pennies in box number 1?

Question

amistre64 · Answer

i dont even know if a hypergeometric would work here ....

amistre64 · Answer

@rational any ideas?

fibonaccichick666 · Answer

...so I may be oversimplifying this, but what is the probability one penny is placed in a box?  Then do the other two as separate events

abdullah1995 · Answer

@FibonacciChick666  i wish it was this simple :P

fibonaccichick666 · Answer

darn.  Then i am of no use, I haven't had a probability course in like 4 years O.O

amistre64 · Answer

[100] [0] [0] [0] ... [0] [0] [0] , 30 choose1 ways?

[99] [1] [0] [0] ... [0] [0] [0] , 30 choose 2 ways?

[98] [1] [1] [0] ... [0] [0] [0] , 30 choose 3 ways?

theres definantly got to be a better way than this lol

darkprince14 · Answer

I was thinking of something like 1 - P(the 97 pennies in the 29 boxes). I just don't now how to approach such a problem..

amistre64 · Answer

how about we go with 0

abdullah1995 · Answer

what grade is this question from ?

amistre64 · Answer

100/30 = 3 1/3  but thats not saying much

darkprince14 · Answer

@abdullah1995 , it's a college level question here in my country

abdullah1995 · Answer

what year of college, and which country

amistre64 · Answer

i cant think of anything .... sig

abdullah1995 · Answer

lol @amistre64

abdullah1995 · Answer

I always hated discrete math :p

darkprince14 · Answer

@abdullah1995 , eh third year, Philippines

abdullah1995 · Answer

nice

darkprince14 · Answer

i'll just close this question. since I have another question... :D