Question

A 1.00g sample of an acid was dissolved in enough water to create 100.0ml of aqueous solution. Titrate it with 15.00ml of 1.058M NaOH. Determine the Formula mass of the acid, assuming two acidic protons per formula unit.

Answer 1

I love these questions. <3

Answer 2

Okay
@ParthKohli will help you :)

Answer 3

Number of milliequivalents of NaOH = \(15 \times 1.058 \times 1 ~\rm meq = 15.087 ~\rm meq\)

Number of milliequivalents of acid = \(15.087~\rm meq\) since equivalents of acid = equivalents of base in a neutralisation reaction.

1 gram acid =====> 15.087 meq

It is given that 1 mmol = 2 meq, so

1 gram acid =====> 7.54 mmol

1/7.54 grams acid =====> 1 mmol

1000/7.54 grams acid ====> 1 mol

132 grams acid ====> 1 mol

Answer 4

i have four answer choices which are
a)21.0g/mol
b)31.5g/mol
c)63.0g/mol
d)126g/mol

Answer 5

Apply yourself.

Answer 6

You wont get direct answer @arturos

Answer 7

I don't understand you mean by milliequivalents

Answer 8

I am still a little confused regarding to what i have to do after i get the moles of NaOH and what the question is telling me when it says "assuming two acidic protons per formula unit"

Answer 9

Because i understand that i need to my moles by 2 but i don't understand why

Answer 10

need to divide my moles by 2*