Question

If \(f(x)=x^2+\sqrt[3]{x}\), what is the value of \(f(-8)\) ?

Answer 1

I dont get this. @tkhunny

Answer 2

Have you considered entering -8 for every occurrence of 'x' in the formulation? That IS what the notation means.

What is the CUBE root of -8? Not the square root.

Answer 3

-2

Answer 4

\(f(x)=-8^2-2\)

Answer 5

\((-8)^{2} + \sqrt[3]{-8} = 64 - 2\)

You have it.

Answer 6

Oh okay. Thank you.

Answer 7

Careful with the notation \(-8^{2}\). It may or may not mean what you want. With the parentheses, it is unambiguous.

Answer 8

It's a math problem from my SAT book and that's how it says it..

Answer 9

It says \(x^{2}\). This implies \((-8)^{2}\). If you write \(-8^{2}\), it MAY mean the same thing. Computer languages have conventions for this sort of thing - called "precedence".

Answer 10

Ohhh. Then, yes. I meant the -8 to be in parenthesis.