Solve the system of equations: x+2y+3z=9 2x-y+2z=11 3x+4y-2y=-4
u know Cramer's Rule?? though its gonna be long @AEB047
No...
put it in an augmented matrix and use elementary row operations to put it in ref or rref
I forget how to do anything with matrices except set them up.
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\[x = \frac{ D_1 }{ D }\] \[y = \frac{ D_2 }{ D }\] \[z = \frac{ D_3 }{ D }\]
@AEB047 THTS THE CRAMER'S RULE
Thanks.
yw....or else do it by elimination method....its also gonna be lengthy ...... @AEB047
I've already tried that.
@AEB047 u didn't get the answer tht way?????o_O
The answers never work for all three equations!
hmmmmm really ,.....i got the answers by both process...want help in tht one or Cramer's one is good???
I've never done the Cramer thing before, so maybe some help with the other method would work better.
ok...:)
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@AEB047
What do you mean by multiply eq 1 from 2? I don't understand how you got equation 4.
hmmhmmmm i did tht to eliminate "x" from both equations....u give a try how would u eliminate "x" from equation 1 and 2
Multiply equation 1 by 5
Sorry, -5
and?????????
i tell u multiply eq 1 by 2 and eq 2 by -1 and add the new equations u get ..........
Okay, I think I get it now. One moment...
okay hav it :))) lol
I've done this all before, actually and I got (2, -1, 3) and it doesn't work in the third equation.
the third equation is 3x + 4y - 2z = -4 u hav written here "3x + 4y - 2y = -4"
and hey @AEB047 (2 , -1 , 3) is the answer ........:)))
Wait, it does work!!!
hmmmmm yes ........
@AEB047 so u done with it????o_IO
Yeah, thanks
u r most welcome....
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