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Mathematics 8 Online
OpenStudy (anonymous):

Solve the system of equations: x+2y+3z=9 2x-y+2z=11 3x+4y-2y=-4

rishavraj (rishavraj):

u know Cramer's Rule?? though its gonna be long @AEB047

OpenStudy (anonymous):

No...

OpenStudy (zarkon):

put it in an augmented matrix and use elementary row operations to put it in ref or rref

OpenStudy (anonymous):

I forget how to do anything with matrices except set them up.

rishavraj (rishavraj):

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rishavraj (rishavraj):

|dw:1430012474438:dw|

rishavraj (rishavraj):

\[x = \frac{ D_1 }{ D }\] \[y = \frac{ D_2 }{ D }\] \[z = \frac{ D_3 }{ D }\]

rishavraj (rishavraj):

@AEB047 THTS THE CRAMER'S RULE

OpenStudy (anonymous):

Thanks.

rishavraj (rishavraj):

yw....or else do it by elimination method....its also gonna be lengthy ...... @AEB047

OpenStudy (anonymous):

I've already tried that.

rishavraj (rishavraj):

@AEB047 u didn't get the answer tht way?????o_O

OpenStudy (anonymous):

The answers never work for all three equations!

rishavraj (rishavraj):

hmmmmm really ,.....i got the answers by both process...want help in tht one or Cramer's one is good???

OpenStudy (anonymous):

I've never done the Cramer thing before, so maybe some help with the other method would work better.

rishavraj (rishavraj):

ok...:)

rishavraj (rishavraj):

|dw:1430013942890:dw|

rishavraj (rishavraj):

@AEB047

OpenStudy (anonymous):

What do you mean by multiply eq 1 from 2? I don't understand how you got equation 4.

rishavraj (rishavraj):

hmmhmmmm i did tht to eliminate "x" from both equations....u give a try how would u eliminate "x" from equation 1 and 2

OpenStudy (anonymous):

Multiply equation 1 by 5

OpenStudy (anonymous):

Sorry, -5

rishavraj (rishavraj):

and?????????

rishavraj (rishavraj):

i tell u multiply eq 1 by 2 and eq 2 by -1 and add the new equations u get ..........

OpenStudy (anonymous):

Okay, I think I get it now. One moment...

rishavraj (rishavraj):

okay hav it :))) lol

OpenStudy (anonymous):

I've done this all before, actually and I got (2, -1, 3) and it doesn't work in the third equation.

rishavraj (rishavraj):

the third equation is 3x + 4y - 2z = -4 u hav written here "3x + 4y - 2y = -4"

rishavraj (rishavraj):

and hey @AEB047 (2 , -1 , 3) is the answer ........:)))

OpenStudy (anonymous):

Wait, it does work!!!

rishavraj (rishavraj):

hmmmmm yes ........

rishavraj (rishavraj):

@AEB047 so u done with it????o_IO

OpenStudy (anonymous):

Yeah, thanks

rishavraj (rishavraj):

u r most welcome....

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