Question

Need help...If someone could explain
Twenty cards are drawn from a pack of cards at random.
The sequence ? is the closest to the probability of drawing a queen or a king from the pack.
5 6 8 2 Q 4 8 3 2 A 2 3 10 J J 4 A 5 3 8
K J 5 8 4 3 6 Q 9 J Q 2 8 Q 9 2 Q A 7 K
3 8 3 2 7 4 J A 6 3 2 A A 6 3 8 6 10 5 4
4 8 6 K J 7 Q 3 A K 2 5 8 9 10 2 4 A 6 7

Answer 1

@cp9454 can you help me with this one? please

Answer 2

we have to find probability of getting king and queen from from a deck of 52 cards or the 20 cards that we have driven randomly.

Answer 3

I need to find which sequence

Answer 4

There are 52 cards
8 cards are Q & K
The sample size is 20
Is this correct so far?

Answer 5

P(Q or K) = P(Q) = 4/52
1/13 + P(A) = 4/52
1/13 = 1/13 + 1/13 = 2/13
confused on the sequence

Answer 6

please, wait a moment

Answer 7

here we have to compute the probability associated to each of your four sequences

Answer 8

for example what is the probability to get a Q from the first sequence

Answer 9

more precisely, what is the probability associated to the first sequence?

Answer 10

1/52

Answer 11

4/52

Answer 12

wait the 5th card out of 20 was a Q

Answer 13

I think that the probability for the first sequence, is:

\[\frac{1}{{52}} \times \frac{1}{{51}} \times \frac{1}{{50}} \times \frac{1}{{49}} \times \frac{1}{{48}}\]

Answer 14

whereas for second sequence, is:
\[\frac{1}{{52}}\]

Answer 15

for third sequence, is:
\[probability = 0\]
since there is neither queen nor king

Answer 16

so the second choice has the best probability

Answer 17

Did I make this question more difficult than it was?

Answer 18

please wait, what is the probability associated to the fourth sequence?

Answer 19

we have the king at the fourth place, so the probability is:
\[\frac{1}{{52}} \times \frac{1}{{51}} \times \frac{1}{{50}} \times \frac{1}{{49}}\]

Answer 20

namely, the second sequence is the right option

Answer 21

Thank you!