Question

Hi everyone! Can anyone look at my posted series and explain to me why y=Coe^(-x) rather than
y=Co(-x) doesn't make any sense to me. Thanks! :o)

Answer 1

I mean I know that "y" is a solution to a first order DE and those solutions are of the form y=Ce^x but this series doesn't seem to mathematically equal that?

Answer 2

lookup series definition of function e^x

Answer 3

http://en.wikipedia.org/wiki/Exponential_function#Formal_definition

Answer 4

gee...that's not confusing at all! bleh
guess I will just accept it and be done
I just thought if you enter a zero in that series, then you get Co(-x) but I guess not

Answer 5

Yes, using the power series definition of e^x is sufficient here.

Answer 6

I guess my assumption to stop at just zero was wrong, you have to keep entering successively larger number for "n"

Answer 7

thanks! :o)

Answer 8

I'm not getting you but i see you figured it out hmm

Answer 9

I just meant that I only enter a zero into the series then multilplied it by Co to get Co(-x) but that is wrong because the idea of an infinite series is NOT to stop at zero and multiply and be done but to continue infinitely entering number n=0,1,2,3,4,etc which I guess equals e^x somehow down the line...that's what I meant

Answer 10

is that correct?

Answer 11

that looks correct!

Answer 12

thanks for clearing that up rational :o)

Answer 13

np:)