Question

see

Answer 1

@rational

Answer 2

use fundamental theorem of calculus
\[\dfrac{d}{dx}\int\limits_a^{g(x)}f(t)\,dt= f(g(x))\cdot g'(x)\]

Answer 3

\[F(x)=\int\limits_1^{3x}\ln(t^2)\,dt\]

\[F'(x)=\ln((3x)^2)\cdot (3x)'~=~3\ln(9x^2)\]

Answer 4

differentiate it again, what do you get ?
use wolfram if u want to as the question asks you to use

Answer 5

3x(ln(x^2)-2+ln(9))+2

Answer 6

@rational

Answer 7

nope. looks you're integrating..

just differentiate F'(x) to get F''(x)

Answer 8

\[F'(x)=3\ln(9x^2)\]
\[F''(x)=?\]

Answer 9

6/x

Answer 10

6/1=6 so 6?

Answer 11

@rational

Answer 12

thats it!