Question

x/2x+2-2x/4x+4+2x-3/x+1 solve the equation

Answer 1

\[\frac{ x }{2x+2 }-\frac{ -2x }{ 4x+4 }+\frac{ 2x-3 }{ x+1 }\]

Answer 2

4x+4
in this term can we take 2 common

Answer 3

??

Answer 4

4(x+1)

Answer 5

yes but just take only 2 out not 4

Answer 6

2(2x+2)

Answer 7

yeah righy

Answer 8

\[\frac{ x }{ 2x+2 }-\frac{ -2x }{ 2*(2x+2) }+\frac{ 2x-3 }{ x+1}\]

Answer 9

in second term can we cancel 2 ??

Answer 10

I don't get when you said we can cancel 2 . from this I must get a LCD to get rid of my fractions right

Answer 11

\[\frac{ -2x }{ 2(2x+2)}\]

Answer 12

in this term 2 in denominator will cancel or cut or divide the 2 in numerator agree??

Answer 13

yes true I agree which would leave neg x over 2x+2

Answer 14

there 2 continuous negative sign so it will become positive agree??

Answer 15

yes

Answer 16

\[\frac{ x }{ 2x+2 }+\frac{ x }{ 2x+2}=??\]

Answer 17

yes

Answer 18

so my lcd is 2x+2 and x+1

Answer 19

\[\frac{ 2x }{ 2x+2 }+\frac{ 2x-3 }{ x+1 }\]

Answer 20

take 2 common from 2x+2

Answer 21

2(x+1)

Answer 22

yeah right now can we cancel 2 ??

Answer 23

true I noticed that as before with th e secon term right

Answer 24

yeah

Answer 25

so after canceling 2

Answer 26

\[\frac{ x }{ x+1 }+\frac{ 2x-3 }{ x+1 }\]

Answer 27

hope you can solve it now

Answer 28

wheres the third term ?

Answer 29

@sam87211

Answer 30

if you sum it up I learn better by seeing the steps im a bit confused because its spced out