http://gyazo.com/73be499a6149614025c549b4b73926c0

Question

anonymous · Answer

use the properties of rhombus. as diagonals bisect each other. EB = DE= 6 cm. By trigonometry $$DE/AD= \sin( \theta)$$ here theta = 30. $$\sin 30 = \sqrt{3}/2$$ AD= DE*2/sqrt(3). Substituting the values AD = 12/sqrt(3). Hope it helps

anonymous · Answer

@bhucho.sen mind helping with a few more?

anonymous · Answer

@TehAustin Not at all

anonymous · Answer

http://gyazo.com/efe2e345e054da5ce46a85f49b7545c0 @bhucho.sen

anonymous · Answer

This requires a little construction. How do you think you will proceed?

anonymous · Answer

IT BE TRUE?

anonymous · Answer

Yes.

anonymous · Answer

But you need to understand why? Because this property will come in Handy. It is not very easy to prove.

anonymous · Answer

http://gyazo.com/7510b12035b482e447ffa32147c2ec40 115 degres right?

anonymous · Answer

No you have made a minor mistake my friend. I think you used the transversal property right??

anonymous · Answer

its abouve 90 degres i saw

anonymous · Answer

It is above 90 but you need to use the properties of transversal to a parellel lines. Hope you understand the term

anonymous · Answer

explain please?

anonymous · Answer

|dw:1430078946877:dw|

anonymous · Answer

yeah

anonymous · Answer

It has certain properties.|dw:1430079018999:dw| sum of the angles marked A and B is 180 degrees