Question

Find the center and radius of the circle whose equation is x^ 2 + y^ 2 - 6x - 2y + 4 = 0

Answer 1

\[\huge\rm x^ 2 + y^ 2 - 6x - 2y + 4 = 0\]
write x's y's separately
\[\huge\rm (x^2 -6x) +(y^2 -2y) +4 =0\]
move 4 to the right side
and apply "completing the* square method for left side "

Answer 2

well my options are
(3,1), r =

(-3,-1), r =

(3,1) r = 6

(9,1), r = 36
so im unsure as to which one it'd be @Nnesha

Answer 3

there are 3 4 step in order to reach t othe answer

Answer 4

s*

Answer 5

would it be (9,2) + 36 ? @Nnesha

Answer 6

nope ....
are you familiar with completing the square method ?

Answer 7

no not at all @Nnesha

Answer 8

completing the square method
divide middle term b by 2 for example in first parentheses \[\huge\rm (x^2 -6x)\]
divide middle term by 2

Answer 9

\[\huge\rm (x + \frac{ b }{ 2 })^2\]
after that take square of 3 and add that to the right side