Am I right?

Question

Am I right?

ohohaye · Answer

attachment

thesmartone · Answer

#1 is wrong.

thesmartone · Answer

Law of sines can be used for any triangle whether it is a right triangle or not.

ohohaye · Answer

ok

thesmartone · Answer

#2 is also wrong...

thesmartone · Answer

and I can't properly see the angles for question 3...

ohohaye · Answer

For the second one is it the last one?

ohohaye · Answer

attachment

ohohaye · Answer

@TheSmartOne

thesmartone · Answer

Question #3 is also wrong .-.

thesmartone · Answer

And again you got #2 wrong... .-.

thesmartone · Answer

For #3,

You have to use the law of cosines:

$\sf\Large b^2 = a^2 + c^2 - 2abcos\beta $

ohohaye · Answer

how do I find C though?

thesmartone · Answer

For #2, 

You have to use the law of sines.

$\sf\Large\frac{sin\alpha}{a}=\frac{sin\beta }{b}=\frac{sin \gamma }{c}$

thesmartone · Answer

Oops, my bad. We have to use law of sines for #3 also.

thesmartone · Answer

Or, if you are really lazy and don't want to do any work, you can use an online calculator to figure it out for you: http://www.mathwarehouse.com/triangle-calculator/online.php

ohohaye · Answer

I have a graphing calculator with me, how wold I type it in for #2?

ohohaye · Answer

Because I typed in sin(7)/7 and got 0.174099062

thesmartone · Answer

$\sf \Large \frac{sin45}{a}=\frac{sin\gamma}{7}$

To find $\sf \gamma$ 

$\sf \gamma = 180 - 110 - 45$

And then do sin of that and solve for $\sf a$

ohohaye · Answer

So Sin(25)/7?

thesmartone · Answer

Now do the cross mutliplication

help_people · Answer

@TheSmartOne may you help me?