Mathematics
13 Online
OpenStudy (anonymous):
give the sine, cosine, and tangent.
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OpenStudy (anonymous):
OpenStudy (anonymous):
i dont know how to figure this out.
OpenStudy (anonymous):
would the sine be 4/3 ?
OpenStudy (acxbox22):
first we need the hypotenuse to find the trig ratios so use the pythagroean theorum to find hypotenuse
OpenStudy (anonymous):
hypotenuse is 12. correct ?
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OpenStudy (anonymous):
and with that in mind sine = 2/3 my mistake. right?
OpenStudy (acxbox22):
nope
8^2+6^2=c^2
100=c^2
c=?
OpenStudy (anonymous):
okay 10
OpenStudy (acxbox22):
yes now do you know the trig ratios?
OpenStudy (acxbox22):
SOH CAH TOA
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OpenStudy (anonymous):
sine = opposite / hypotenuse
cosine = adjacent / hypotenuse
tangent = opposite / adjacent
OpenStudy (anonymous):
okay so sine = 4/5
OpenStudy (acxbox22):
yes so lets identify the opposite,adjacent,and hypotenuse of angle E
opposite=8
adjacent=6
hypotenuse=10
now just use your ratios and i will check
OpenStudy (acxbox22):
yes correct
OpenStudy (anonymous):
cosine = 3/5
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OpenStudy (acxbox22):
yes
OpenStudy (anonymous):
tangent = 4/3
OpenStudy (acxbox22):
yes good job
but remember its sin(angle e) not just sine=
OpenStudy (anonymous):
okay. :) so i could write it (angle E) sine = 4/5 and it would be correct? or would i have to write it sin (angle E)
OpenStudy (acxbox22):
generally its the second way
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OpenStudy (acxbox22):
like for any thing it would be \[\sin (\theta)\]
OpenStudy (acxbox22):
where that symbol means theta or just any angle measure
sorta like x for angles
OpenStudy (anonymous):
okay and i would do that for cos and tan then as well, right?
OpenStudy (acxbox22):
correct :)