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Mathematics 13 Online
OpenStudy (anonymous):

give the sine, cosine, and tangent.

OpenStudy (anonymous):

OpenStudy (anonymous):

i dont know how to figure this out.

OpenStudy (anonymous):

would the sine be 4/3 ?

OpenStudy (acxbox22):

first we need the hypotenuse to find the trig ratios so use the pythagroean theorum to find hypotenuse

OpenStudy (anonymous):

hypotenuse is 12. correct ?

OpenStudy (anonymous):

and with that in mind sine = 2/3 my mistake. right?

OpenStudy (acxbox22):

nope 8^2+6^2=c^2 100=c^2 c=?

OpenStudy (anonymous):

okay 10

OpenStudy (acxbox22):

yes now do you know the trig ratios?

OpenStudy (acxbox22):

SOH CAH TOA

OpenStudy (anonymous):

sine = opposite / hypotenuse cosine = adjacent / hypotenuse tangent = opposite / adjacent

OpenStudy (anonymous):

okay so sine = 4/5

OpenStudy (acxbox22):

yes so lets identify the opposite,adjacent,and hypotenuse of angle E opposite=8 adjacent=6 hypotenuse=10 now just use your ratios and i will check

OpenStudy (acxbox22):

yes correct

OpenStudy (anonymous):

cosine = 3/5

OpenStudy (acxbox22):

yes

OpenStudy (anonymous):

tangent = 4/3

OpenStudy (acxbox22):

yes good job but remember its sin(angle e) not just sine=

OpenStudy (anonymous):

okay. :) so i could write it (angle E) sine = 4/5 and it would be correct? or would i have to write it sin (angle E)

OpenStudy (acxbox22):

generally its the second way

OpenStudy (acxbox22):

like for any thing it would be \[\sin (\theta)\]

OpenStudy (acxbox22):

where that symbol means theta or just any angle measure sorta like x for angles

OpenStudy (anonymous):

okay and i would do that for cos and tan then as well, right?

OpenStudy (acxbox22):

correct :)

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