Question

can someone just tell me if these calc answers are right:

Answer 1

for the first one i did this: \[\frac{ 1 }{ 5-0 }\int\limits_{0}^{5} (60x ^{3}-650x ^{2}+1200x+4500) dx\]

Answer 2

The first one is correct. I'm getting 11875/3 = 3958.333333

Answer 3

the second one is not correct

Answer 4

perfect same here but I'm not sure if i did it right. Did u use the integral i provided or did u come up with it on your own and then integrate? Now for the second one i used this but i'm honestly not sure

Answer 5

I integrated what you wrote

Answer 6

oh but i'm not sure if my integral is right lol

Answer 7

your integral for the first one is correct

Answer 8

how did you get the answer to the second one?

Answer 9

i used this integral: \[\int\limits_{-1}^{1} (2-x ^{2})^{2}-(9x ^{2})^{2} dx\]

Answer 10

you are supposed to have

\[\Large \int_{-1}^{1} \left[(2-x^2)-(x^2)\right]^2dx\]

notice how I subtracted the functions first, and then squared the difference

Answer 11

and idk where you got the 9 from

Answer 12

my bad the 9 was an accident i was trying to the the parenthesis but i didn't hold shift haha

Answer 13

and ok that's because it's a volume right ?

Answer 14

ah gotcha lol

Answer 15

the integrand \[\Large \left[(2-x^2)-(x^2)\right]^2\] represents the area of any cross section. When you combine those areas (like stack them up) by integrating, they form a 3D solid volume

Answer 16

ok i see. So the answer is 4.26667

Answer 17

write that as a fraction

Answer 18

64/15 sorry my bad i took so long. Phone call!

Answer 19

that's perfectly fine

Answer 20

64/15 is correct

Answer 21

and i'm assuming the last one is correct right? because u square it after ?

Answer 22

still checking that one

Answer 23

I'm guessing there's a 4th answer choice that is cut off? Or no?

Answer 24

ya the forth answer is "none of the above"

Answer 25

ok thanks