How do you find "b" in the equation y=mx+b? (On a graph)
you need the slope and the two points
The equation i have is y=3x+ (blank). The points are (-1, 1), and (0,4).
which point crosses the y intercept
(0,4)
plug that into the equation by replacing the x and y
So it would be 0x+(blank)=4?
first find you slop using your two points
So it would be y/x, and that is 4/0?
i think your b would be 4
So the answer would be y=3x+4?
i think so try graphing it
For the question there is already a graph. I just need to figure out the equation.
graph you equation and see if it matches
How would I confirm that y=3x+4 is correct for the graph?
Oh, yes it matches! Thank you very much!
no problem
Just a quick recap :) (For future reference) If you are given a graph, and you are looking for the equation in the form y=mx+b First thing you have to know is m stands for slope. To find the slope from the graph: 1. Pick two points 2. Plug them in the formula \(\sf \Large m=\frac{y_2-y_1}{x_2-x_1}\) Second thing you have to know is "b" stands for y-intercept (0, y). To find the value of the y-int, look from your graph and anything that passes through the y axis will be your y-intercept or b. Now, once you find the m (slope) and the b(y-int), you can easily replace them in the general formula \(\sf y=mx+b\) ^_^
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