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Solve this system of equations using the inverse of a matrix. -x + y = 8 4x + 3y = 12 x − 7y + z = 15 x = 4, y = 68, and z = 5.39 x = 68, y = 5.39, and z = 4 x = -1.76, y = 6.24, and z = 60.76 x = 6.24, y = -1.76, and z = 60.76 x = 72, y = -4, and z = 12.78 [Hint: AX = B and X = BA-1]
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HI!!
i surely would not use that method!
hey
:)
\[-x + y = 8\\ 4x + 3y = 12\] can be solved very easily
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how do you solve?
multiply the first equation by \(-3\) and add
or multiply the first equation by \(4\) and add
either way
-3x+-3y=-24?
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by \(-3\) you get \[3x-3y=-24\\ 4x+3y=12\] add and the y's go bye bye
ok
once you have \(x\) and \(y\) plug them in to the third equation to find \(z\)
so 3x=-24
and 4x=12?
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...
I am just going to take it as C
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