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Mathematics 16 Online
OpenStudy (anonymous):

Alice spins the spinner 3 times. What is the probability that she spins an A, then a B, and then a C? http://static.k12.com/calms_media/media/332000_332500/332448/2/580a1a69ea83d3dd36df179e9d8ab7a5003d26d9/MS_ALG_A2_04_quiz_Q2_question.gif A. 1/3 B. 1/9 C. 1/27 D. 1/12

OpenStudy (anonymous):

@iGreen

OpenStudy (mathmate):

@sonic400539 Very smart way of tagging people one at a time without leaving a trace! Anyway, what is the probability of landing on A for the first spin?

OpenStudy (igreen):

Lol^

OpenStudy (anonymous):

1/3

OpenStudy (igreen):

The probability of spinning A, B, or C are the same, so when we find one, we can multiply it by itself 2 times.

OpenStudy (igreen):

Yep, you got it.

OpenStudy (igreen):

Now multiply it by itself 2 times.

OpenStudy (anonymous):

xD Yeah, I always clear them so I don't look desperate.

OpenStudy (mathmate):

Good, what is the probability of landing on B in a subsequent spin?

OpenStudy (anonymous):

2/3?

OpenStudy (mathmate):

B is still one third of the whole circle, so there is not a better probability than A, do you agree?

OpenStudy (anonymous):

Yes, I agree. It makes sense.

OpenStudy (mathmate):

What about C, again in a subsequent spin?

OpenStudy (anonymous):

1/3

OpenStudy (anonymous):

All have an equal chance, correct?

OpenStudy (mathmate):

Yes, each one has equal chance. Now, the experiment of getting A, then B, then C is called a multi-step experiment. The probability is the product of the three individual probabilities IF the steps are independent of each other.

OpenStudy (mathmate):

Here, independence means that the result of one spin does NOT affect the result of subsequent spins, which is the case here, so the multiplication rule mentioned above applies.

OpenStudy (mathmate):

@sonic400539 ok so far?

OpenStudy (anonymous):

I'm following it. (So far.)

OpenStudy (mathmate):

So how would you find the answer to the problem? If you have doubts, reread what I just posted to make sure you understand it. It is the key to your answering ALL similar problems.

OpenStudy (anonymous):

I believe that it is B because 1/3 is A, B, and C and when added you have a total probability of 1/9.

OpenStudy (anonymous):

Wait, the answer is C. 1/27. The chances are correct. Thanks for the help! Question: Closed

OpenStudy (mathmate):

Exactly: Good work! \(\color{blue}{\Large\checkmark}{Way~to~go!}\)

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