WILL MEDAL AND FAN!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! @igreen @answermyquestions @lordhelix8th What is the length of RM when TS = 12 cm, TP = 11 cm, and RO = 15 cm? Round to the nearest tenth of a centimeter. http://static.k12.com/calms_media/media/1579000_1579500/1579257/1/b94d5af516d6cf8e252efe065e0f05fde897532c/MS_IMC-150123-1306011.jpg
Well?
@sonic400539 do you know?
We need to use the Pythagorean Theorem
oh great....
Are you familiar with it?
nope
Read this and tell me if you understand it http://www.mathsisfun.com/pythagoras.html
\(\small\color{#AC58FA}{Would~you~mind~just~working~me~through~the~answer?}\)
Define working through the answer?
Okay, so we want to find OM first to complete the right triangle.
OM can be easily found :P
OM = 1/2 * TS
but they need to know what the Pythagorean Theorem is first...
\(\small\color{#AC58FA}{I~do~already.}\)
Okay, can you give us a brief summary?
\(\small\color{#AC58FA}{the~Pythagorean~theorem~or~Pythagoras's~theorem~is~a~statement~about~the~sides~of~a~right~triangle.}\)
nice copy and paste
who says i copied and pasted?
Hmmmm... wikipedia does http://simple.wikipedia.org/wiki/Pythagorean_theorem
Okay, let me give a brief summary of it. Btw, it's okay to say you don't know what it is.
I don't have time for this. My stupid keyboard is glitched. Everytime i post something, the text stays in the box and when i press backspace it goes back another page.
First off, what is the formula for the Pythagorean Theorem?
The Pythagorean Theorem is a formula used to find any side of a right triangle when given the two other sides. The formula is \(\sf a^2 + b^2 = c^2\). Where 'a' and 'b' are the two legs of the triangle, and 'c' is the hypotenuse.
@sleepyjess Lol, this is why 2 people helping gets frustrating..
lol
You answered the question :P
Yes, that's what I meant by frustrating..lol.
xD
Anyway, in this situation, KM is the hypotenuse, 'c', and RO and OM are the two legs.
RM*
We are already given RO, and TS. And like I stated before, OM = 1/2 * TS
So, can you find OM? @CheesecakeKitten
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