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OpenStudy (anonymous):
give me a sec
OpenStudy (igreen):
Area of a triangle:
\(\sf A = \dfrac{1}{2}bh\)
Plug in what we know:
\(\sf A = \dfrac{1}{2}(17)(8)\)
Simplify
OpenStudy (anonymous):
^
OpenStudy (igreen):
Area of a parallelogram:
\(\sf A = bh\)
\(\sf A = (17)(6)\)
OpenStudy (igreen):
Simplify those then add them up, you get your answer.
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OpenStudy (anonymous):
68
OpenStudy (anonymous):
no 102
OpenStudy (vianne):
Well you both got correct. Now just add both of them up.
OpenStudy (anonymous):
No 136
OpenStudy (anonymous):
WAIITTT 170
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OpenStudy (vianne):
68 is for the triangle..
102 is for the parallelogram..
Where are you getting these random numbers? Please explain your methods. :)
OpenStudy (anonymous):
its 170 and i typed in the wrong numbers
OpenStudy (vianne):
Ok, so that's your final answer correct? :P
OpenStudy (igreen):
170 is correct.. :P
OpenStudy (vianne):
^
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OpenStudy (anonymous):
=^.^=
OpenStudy (anonymous):
:D
OpenStudy (igreen):
Area of a triangle:
\(\sf A = \dfrac{1}{2}bh\)
Plug in what we know:
\(\sf A = \dfrac{1}{2}(17)(8)\)
Multiply:
\(\sf A = 68\)
Area of a parallelogram:
\(\sf A = bh\)
\(\sf A = (17)(6)\)
Multiply:
\(\sf A = 102\)
Add them:
\(\sf 102 + 68 = \boxed{170}\)