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Mathematics 7 Online
OpenStudy (anonymous):

@blonde_gangsta http://prntscr.com/6yr590

OpenStudy (anonymous):

give me a sec

OpenStudy (igreen):

Area of a triangle: \(\sf A = \dfrac{1}{2}bh\) Plug in what we know: \(\sf A = \dfrac{1}{2}(17)(8)\) Simplify

OpenStudy (anonymous):

^

OpenStudy (igreen):

Area of a parallelogram: \(\sf A = bh\) \(\sf A = (17)(6)\)

OpenStudy (igreen):

Simplify those then add them up, you get your answer.

OpenStudy (anonymous):

68

OpenStudy (anonymous):

no 102

OpenStudy (vianne):

Well you both got correct. Now just add both of them up.

OpenStudy (anonymous):

No 136

OpenStudy (anonymous):

WAIITTT 170

OpenStudy (vianne):

68 is for the triangle.. 102 is for the parallelogram.. Where are you getting these random numbers? Please explain your methods. :)

OpenStudy (anonymous):

its 170 and i typed in the wrong numbers

OpenStudy (vianne):

Ok, so that's your final answer correct? :P

OpenStudy (igreen):

170 is correct.. :P

OpenStudy (vianne):

^

OpenStudy (anonymous):

=^.^=

OpenStudy (anonymous):

:D

OpenStudy (igreen):

Area of a triangle: \(\sf A = \dfrac{1}{2}bh\) Plug in what we know: \(\sf A = \dfrac{1}{2}(17)(8)\) Multiply: \(\sf A = 68\) Area of a parallelogram: \(\sf A = bh\) \(\sf A = (17)(6)\) Multiply: \(\sf A = 102\) Add them: \(\sf 102 + 68 = \boxed{170}\)

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