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What volume of concentrated hydrochloric acid (12.0 M HCl) is required to make 2.0 liters of a 3.0 M HCl solution?
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If you have 12 M HCl \(\sf \color{red}{M_1}\) and you want a concentration of \(\sf \color{red}{M_2}\) and a total volume of 2.0 L \(\sf \color{blue}{V_2}\) Then simply use the dilution equation: \(\sf \color{red}{M_1}\)V\(_1\) = \(\sf \color{red}{M_2}\)\(\sf \color{blue}{V_2}\) rearrange using algebra to solve for the initial volume. That means that you're using V\(_1\) liters of HCl and diluting the rest with water to make a total of 2.0 L. Does that make sense?
This is not qualitative, and hence, your concentration is simply approximate.
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