What is the distance between points (2, 8) and (7, 5)? Round to the nearest tenth of a unit.

____UNITS

Question

What is the distance between points (2, 8) and (7, 5)? Round to the nearest tenth of a unit.

____UNITS

igreen · Answer

$\sf d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

(2, 8), (7, 5)
x1 y1 x2 y2

igreen · Answer

Plug the numbers in and simplify.

anonymous · Answer

@welshfella

anonymous · Answer

@sammixboo

igreen · Answer

$\sf d = \sqrt{(7-2)^2 + (5-8)^2}$

7 - 2 = ?
5 - 8 = ?

anonymous · Answer

7-2 is 5

5-8 is 3

igreen · Answer

-3*

igreen · Answer

So we have:

$\sf d = \sqrt{(5)^2 + (-3)^2}$

Now simplify 5^2 and -3^2, do you know how?

anonymous · Answer

ummm nah D:

igreen · Answer

Okay, here's the thing with exponents.

The small number at the top tells us how many times to multiply the number at the bottom.

$\sf 6^2 \rightarrow 6 \times 6 \rightarrow 36$

$\sf 10^4 \rightarrow 10 \times 10 \times 10 \times 10 \rightarrow 10000$

Get it?

anonymous · Answer

oh yeah i know what XD exponents

igreen · Answer

Yep, so can you simplify $\sf 5^2$ and $\sf -3^2$?

anonymous · Answer

do you multiply it i got -225

igreen · Answer

No, we add it.

anonymous · Answer

thats makes way more sense, okay i finally got it thankyou so much dude, seriosuly thankyouuu

igreen · Answer

No problem, after you add it, find the square root and round it, that will be your answer.

anonymous · Answer

so is the answer 5.8?