Question

Complete the equations of the system in slope-intercept form. Use a decimal for the slope if necessary.




Line 1
x y
0 3
1 5

Line 2
x y
–1 1
–2 –1




Line 1: y = x +

Line 2: y = x +

Answer 1

@iGreen

Answer 2

First, find the slope.

\(\sf m = \dfrac{y_2-y_1}{x_2-x_1}\)

Line 1:

(0, 3), (1, 5)
x1 y1 x2 y2

So we have:

\(\sf m = \dfrac{5-3}{1-0}\)

Simplify

Answer 3

2/1

Answer 4

Yep, or 2.

Now plug it into point-slope form along with any of the two points.

Let's use (1, 5).

Put it in point-slope form first.

\(\sf y - y_1 = m(x - x_1)\)

Where \(\sf y_1\) is the y-value of the point, \(\sf x_1\) is the x-value of the point, and \(\sf m\) is the slope.

So we have:

\(\sf y - 5 = 2(x - 1)\)

Distribute 2 into the parenthesis, can you do that?

Answer 5

y-5=2x-2

Answer 6

Yep, now add 5 to both sides.

Answer 7

y=2x-3

Answer 8

Not quite, -2 + 5 = ?

Answer 9

-7

Answer 10

Check again.

Answer 11

but your adding negatives

Answer 12

+3

Answer 13

@igreen