Question

A dealer dealt the following cards from a shuffled deck:

3 , 2 , 2 , A , K , Q , K , 5 , 2 , 6
4 , 5 , K , 2 , 7 , 6 , A , J , J , A

What was the experimental probability of dealing a black card?

can someone help will give medal 8 cards are black and12 are red pleaaaasseee help do i divide 20 by 8 or 8 by 20

Answer 1

@amistre64 can you help me please

Answer 2

@mathmate can you help

Answer 3

@dan815 can you help

Answer 4

Yes, your answer (8/(12+8)=8/20=2/5) is correct (if there are 8 black and 12 red cards).
The experimental probability is the number of observed successes over total number of trials.

Answer 5

thanks @mathmate could you help with one more

Answer 6

Just post it and I'll see!

Answer 7

A businessman bought a car dealership that is incurring a loss of $500,000 a year. He decided to strategize in order to turn the business around. In addition to the $500,000 annual loss, his fixed cost for running the dealership on a monthly basis is $5,000. The number of cars sold per week and their probabilities mimic the outcomes of three coins being flipped. The number of cars sold in a week was observed to be the same as the number of tails that appear when three coins are flipped. See the distribution:

Answer 8

Given that there are 52 weeks in a year, what is the expected revenue per car (rounded to the nearest dollar) that has to be made in order to break even in the first year

Answer 9

The distribution (that you have not posted), is it
0 1/8
1 3/8
2 3/8
3 1/8
?

Answer 10

yea sorry

Answer 11

forgot to post that part

Answer 12

From the distribution, can you find the expectation of the number of tails when we flip three (fair) coins?

Answer 13

1.25?

Answer 14

im not good with this:(

Answer 15

Expectation is defined as:
\(E[X]=\sum xP(x)\)
Have you learned that before?

Answer 16

i studied it but it dont make sense

Answer 17

In this case, E[X]=0(1/8)+1(3/8)+2(3/8)+3(1/8)=0.5

Answer 18

Sorry, it should read =1.5

Answer 19

So on the average, the dealer sold 1.5 cars per week.

Answer 20

or 52*1.5=78 cars per year.

Answer 21

assume 8 weeks
-----------------------

0 1/8

0 cars are sold 1times out of 8: 0(1) = 0
-----------------------

1 3/8

1 cars are sold 3times out of 8: 1(3) = 3
-----------------------

2 3/8

2 cars are sold 3 times out of 8: 2(3) = 6
-------------------------

3 1/8

3 cars are sold 1 times out of 8: 3(1) = 3
-------------------------

how many cars are sold on average in 8 weeks?

0 + 3 + 6 + 3

Answer 22

Now what you need to do is to calculate the total loss, including the annual loss, and 12 times the monthly loss.
To break even, the dealer has to make profit on each of the 78 cars sold to cover the loss. So divide the total loss by 78 to get the profit needed to break even.

Answer 23

o+3+6+3 would give the numer of losses

Answer 24

@amistre64

Answer 25

@mathmate whats the total loss

Answer 26

" In addition to the $500,000 annual loss, his fixed cost for running the dealership on a monthly basis is $5,000."
What would that cost over a year?

Answer 27

the number of cars sold per week

Answer 28

..."or 52*1.5=78 cars per year."