Question

I need help with theoretical and percent yield. I did a lab experiment and I need to finish the lab report now.

Answer 1

Here's the process.

Answer 2

actual yield - theoretical yield/theoretical yield x 100

So take how much you got when the actual experiment was formed, then subtract from that the amount you would have gotten in an ideal scenario(theoretical yield, how much you calculated), divide that by theoretical yield and multiply by 100 to get percent out of a hundred

Answer 3

I can't figure out how to get the theoretical yield. :/ I'm supposed to use the chemical equation, but I can't figure out how. This is the equation. 2Al (s) + 2KOH + 22H2O + 4H2SO4 -> 2KAl(SO4)2 * 12H2O (s) + 3H2 (g)

Answer 4

And you're trying to see how much potassium alum can be made?

step 1 determine limiting reagent. take the mass of each reagent convert to molar mass, convert to moles of Kalum(potassium alum) using stoichiometric ratio (coefficients from balanced equation) then use molar mass of Kalum to find gram of Kalum. <- you need to do that for EACH reactant, the one the provides the lowest number is your limiting reagent.

One you know the amount of potassium alum that can be produced from your limiting reagent, you have you theoretical yield! just 1 step, so easy ;)

I hope this makes sense, let me know if there's anything you need more clarification on

Answer 5

That's good! Thank you!

Answer 6

Can you help me on one or so more?

Answer 7

awesome! sure I'll try