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OpenStudy (anonymous):
1. Let f(x)=x^3-2x. Simplify the expression f(x+h)-f(x)/h
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OpenStudy (anonymous):
Seems you are using definition of a derivative
Nnesha (nnesha):
first you should find f(x+h)
so replace f(x) <---x in this equation by x+h
OpenStudy (anonymous):
You have to plug in (x+h) wherever there is an x in your function
OpenStudy (anonymous):
\[\frac{ (x+h)^3-2(x+h)-x^3-2x }{ h }\] so this
OpenStudy (anonymous):
You can do the simplification I think you just might have had trouble with the set up, I hope that helps.
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Nnesha (nnesha):
\[\huge\rm f(\color{red}{x})= x^3-2x \]
substitute x+h
Nnesha (nnesha):
\[\huge\rm \frac{ (x+h)^3-2(x+h)- \color{blue}{(}x^3-2x\color{blue}{)} }{ h }\]
parentheses!!!
OpenStudy (anonymous):
Good call! :)
OpenStudy (anonymous):
so x^3-2x is the answer?? @Nnesha
Nnesha (nnesha):
nope how did you get that ?
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OpenStudy (anonymous):
never mind, can you help me get the answer
Nnesha (nnesha):
okay first solve this (x+h)^3
OpenStudy (anonymous):
x+h^3
Nnesha (nnesha):
ahh nope
(x+h)^3 is same as (x+h)(x+h)(x+h)
Nnesha (nnesha):
so either foil that or you can use this rule
\[\rm (a+b)^3 = a^3 +3a^2b+3ab^2+b^3\]
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