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Mathematics 16 Online
OpenStudy (anonymous):

Need help will fan and medal

OpenStudy (anonymous):

The steps to derive the quadratic formula are shown below: Step 1 ax2 + bx + c = 0 Step 2 ax2 + bx = - c Step 3 x squared over a plus b over a times x equals negative c over a Step 4 x2 + b over a times x plus b squared over 4 times a squared equals negative c over a plus b squared over 4 times a squared Step 5 x2 + b over a times x plus b squared over 4 times a squared equals negative 4 multiplied by a multiplied by c, all over 4 multiplied by a squared plus b squared over 4 times a squared Step 6 the square of the quantity x plus b over 2 times a equals b squared minus 4 multiplied by a multiplied by c, all over 4 times a squared Step 7 x plus b over 2 times a equals plus or minus square root of the quantity b squared minus 4 times a times c over 4 times a squared equals plus or minus square root of b squared minus 4 times a times c, all divided by 2 times a Step 8 x = -negative b over 2 times a plus or minus square root of b squared minus 4 times a times c, all divided by 2 times a Step 9 x = negative b plus or minus square root of b squared minus 4 times a times c, all divided by 2 times a Which of the following is the first incorrect step? Step 2 Step 3 Step 4 Step 7

OpenStudy (anonymous):

@Preetha @confluxepic @Phebe @e.mccormick

OpenStudy (anonymous):

@whpalmer4 @Quan99 @jim_thompson5910 @.....anyone?

jimthompson5910 (jim_thompson5910):

can you post a screenshot of the problem?

OpenStudy (anonymous):

one sec

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910 ?

jimthompson5910 (jim_thompson5910):

I'm looking it over now

OpenStudy (anonymous):

okay

jimthompson5910 (jim_thompson5910):

You have the correct answer. Step 3 is the first incorrect step because there shouldn't be an \(\Large \frac{x^2}{a}\) term. It should simply be \(\Large x^2\) instead.

OpenStudy (anonymous):

Okay thanks! I thought so but I checked other discussions about this one and they put different things.

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