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Mathematics 6 Online
OpenStudy (anonymous):

Raymond has taken a position as the navigator on a speed boat racing team. The team entered a race that starts at Daytona Beach, Florida. The first leg of the race course has them traveling due east for 140 miles. They turn right and travel 160 miles for the second leg of the race. They make another right turn to start the third and final leg of the race, in which they will travel 180 miles back to the starting point at Daytona Beach. What is the measure of the turn between the second and third legs of the race? Round your answer to the nearest degree.

OpenStudy (anonymous):

@EclipsedStar

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

what kind of a traingle does the course make?

OpenStudy (anonymous):

it does not tell or show

OpenStudy (amistre64):

this is called critical thinking skills. you need to assess it from the information given. draw the course ....

OpenStudy (amistre64):

it most surely "tells" its up to you to determine it

OpenStudy (anonymous):

The race course forms an acute triangle, im thinking

OpenStudy (amistre64):

travel east, and turn right.. the very implication is that this is a right triangle |dw:1430180995400:dw|

OpenStudy (amistre64):

fill in the details |dw:1430181040746:dw| now, you must have been taught some trigonometry, otherwise this is not going to get us anywhere.

OpenStudy (anonymous):

im totally confussed bc the hint on the paper says it is a acute angle and that the missing angle is about 48degrees

OpenStudy (amistre64):

the angle is less then 90, so its acute ... but we need to know trigonometry in order to solve this. that is where you come in. you have to tell me what trig function would be most appropriate for this setup.

OpenStudy (anonymous):

Law of Cosines

OpenStudy (anonymous):

i think

OpenStudy (amistre64):

interestingly enough we 'could' use that ... but theres a much simpler approach use the tangent function

OpenStudy (amistre64):

|dw:1430181411425:dw| \[tan(A)=\frac{over}{next.to}\]

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