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please help me
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\[\frac{ 4y^2 }{8y^4+16y^3 }\]
What is a common factor?
4y^2
Right, so take that out of everything and what are you left with?
Im left with \[2y^2+3y\]
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You don't divide, you subtract. 8y^4-4y^2 = what
?
the common factor on the bottom line is 8y^2
it's 2y(y+2)
right?
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Nevermind
8-4 is what
Dont give up, we'll break it down so you get it
I get it the answer is 2y(y+2)
Thats ont correct
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The 1/ is pretty important and your obttom is wrong as well
ok thank you both
The correct answer is \[1/2y^2+4y\]
yes you're right. thanks
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