Question

Factor this polynomial: 15/4-x-x^2

Answer 1

is that \[\frac{15}{4-x-x^2}\]

Answer 2

the way you wrote is vague

Answer 3

\[\frac{ 15 }{ 4 } -x-x^2\] is what I meant

Answer 4

to factor that need to get to ax^2+bx+c
form

Answer 5

what way do you know of for factoring

Answer 6

I know, I can do that.\[-x^2-x+\frac{ 15 }{ 4 }\]

Answer 7

rather i want to say what ways

Answer 8

Throw some at me, I can't really name 'em all...

Answer 9

that won't help you that much it is still the same

Answer 10

the most used one is quadratic

Answer 11

formula

Answer 12

we can do this \[1/4(-4x^2-4x+15)\]

Answer 13

I know it's the same, you said I needed to put it into ax^2+bx+c form, so I did. I know quadratic formula.

Answer 14

can you factor now using any other method you know of

Answer 15

that's not what i meant see my comment
you just rearranged the terms in descending order

Answer 16

\[1/4(-2x ~~~~~~~)(2x~~~~~~~)\]

Answer 17

what do you think will be in the blank

Answer 18

5 and 3?