Question

What is the value of this expression when n approaches infinity?

Answer 1

\[4-\frac{ 4 }{ n }+\frac{ 5 }{ 9 }+\frac{ 15 }{ 3n^2 }\]

Answer 2

What does this approach \(\Large\frac{1}{\infty}\) ?

Answer 3

Any ideas?

Answer 4

20
10
5
4
1

Answer 5

1/infinity=0

Answer 6

\(\Large\frac{1}{HUGE}=\small small\)
\(\Large\frac{1}{\infty}=\small 0\)

Answer 7

Yes

Answer 8

4/infinity is ?

Answer 9

?

Answer 10

\(\Large\frac{4}{HUGE}= \small small \) correct?

Answer 11

the answer is 4?

Answer 12

if you divide a small number by a very very huge number, the result is small that means it will approach to 0

Answer 13

I got 4 somehow

Answer 14

infinity is continuous , not a number, but it's very huge. Any number divided by infinity is small, therefore approaches zero.

Answer 15

How did you get 4?

Answer 16

4-0+0+15/infinity = 4

Answer 17

I see a 4.55555555555555555555

Answer 18

\(4−\frac{4}{n}+\frac{5}{9}+\frac{15}{3n^2}=4-0+\frac{5}{9}+0=\frac{41}{9}\)

Answer 19

I get a 4.555555555555555555555555

Answer 20

...

Answer 21

yes, that is correct

Answer 22

so... is it 4 or 5?

Answer 23

My apologies, i misunderstood you earlier, i thought you were replying to my question regarding 4/infinity and i thought you said that answer was 4.

Answer 24

Your answer is 4.5, round it to 5

Answer 25

ok