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OpenStudy (anonymous):
The position of an object at time t is given by s(t) = -4 - 2t. Find the instantaneous velocity at t = 6 by finding the derivative.
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OpenStudy (misty1212):
HI!!!
OpenStudy (misty1212):
it is a line right?
OpenStudy (misty1212):
rate of change = slope is all
derivatives or otherwise
OpenStudy (anonymous):
Yes it's a line!
OpenStudy (misty1212):
the slope is \(-2\) right?
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OpenStudy (anonymous):
@misty1212 after u done help me with my problem plz!
OpenStudy (misty1212):
the \(t=6\) part got nothing to do with it
slope is a constant
OpenStudy (misty1212):
@qwertyboy56 sorry i don't know any geometry
OpenStudy (anonymous):
Okay but what does slope have to do with it?
OpenStudy (misty1212):
the slope is the rate of change
that is what you are being asked for
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OpenStudy (misty1212):
Find the instantaneous velocity = rate of change
for a line, derivative = slope
OpenStudy (anonymous):
Are you sure? Not doubting you, but it just seems too easy.
OpenStudy (misty1212):
it is easy yes i agree
OpenStudy (misty1212):
you can take the derivative if you like
you will get \(-2\)
OpenStudy (perl):
s ' (t) =-2 for any t
therefore
s ' (6) = -2
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