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Mathematics 13 Online
OpenStudy (rebeccapink6398):

WILL MEDAL+FAN!!!! Please help with fractions

OpenStudy (rebeccapink6398):

OpenStudy (legends):

Im thinking its C but Im not 100% sure sorry

OpenStudy (rebeccapink6398):

can you explain how you got your answer? i want to learn :)

OpenStudy (rebeccapink6398):

@sammixboo

ganeshie8 (ganeshie8):

start by converting the mixed fraction into improper fraction : \[5\dfrac{1}{4}=\dfrac{5*4+1}{4}=\dfrac{21}{4}\]

ganeshie8 (ganeshie8):

therefore the given expression is \[\dfrac{21}{4}\cdot\dfrac{8}{9}\cdot \dfrac{8}{21}\]

ganeshie8 (ganeshie8):

cancel the common factors top and bottom simplify

OpenStudy (rebeccapink6398):

how to i simplify frcations?

ganeshie8 (ganeshie8):

To multiply two fractions, simply multiply numerators separately and multiply denominators separately : \[\dfrac{a}{b}\cdot \dfrac{c}{d}=\dfrac{a\cdot c}{b\cdot d}\]

ganeshie8 (ganeshie8):

\[\dfrac{21}{4}\cdot\dfrac{8}{9}\cdot \dfrac{8}{21}=\dfrac{21\cdot 8\cdot 8}{4\cdot 9\cdot 21}\]

ganeshie8 (ganeshie8):

do you see anything cancels out ?

OpenStudy (rebeccapink6398):

i am not sure what you mean by "cancels out" but dont we need to have common denominators

ganeshie8 (ganeshie8):

very good question common denominators is needed for "adding/subtracting" fractions multiplying two fractions is simple, you just multiply numerators separately and denominators separately. it is easier compared to adding/subtracting

ganeshie8 (ganeshie8):

\[\dfrac{21\cdot 8\cdot 8}{4\cdot 9\cdot 21}\] \(21\) is there in both top and bottom, so cancel it and get \[\require{cancel}\dfrac{\cancel{21}\cdot 8\cdot 8}{4\cdot 9\cdot \cancel{21}}\] \[\dfrac{ 8\cdot 8}{4\cdot 9}\]

OpenStudy (rebeccapink6398):

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