2. Using the formula qunknown metal = m × c × ΔT, calculate the specific heat of the metal. Use the data from your experiment for the unknown metal in your calculation. Show ALL your work. The data is Mass of metal: 25.605g Water Measurement: 24.91mL Water Temp: 25.1 C Metal temp: 100.2 C Mixture temp: 28.7 C I will award a medal and fan.
The idea is to find the amount of heat gained by the water. This is the amount of heat lost by the metal (assuming the reaction is insulated).
Can help explain how I do that? I'm really confused.
The heat absorbed by the water is \[q_{water}=m _{water}c _{water}DeltaT _{water}\] What do you get for that?
qwater= 24.91 x 4.16 j x 3.6= 374.846 J
@JoannaBlackwelder Thanks so much just getting that helped so much :)
No worries :-)
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