Which equations show that the set of whole numbers is not closed under subtraction? Choose all answers that are correct. A. 1 – (–2) = 3 B. 1 – 2 = –1 C. 2 – 0 = 2 D. 2 – 4 = –2
@water_girl_101 @freckles @Mimi_x3
can someone help me?
Okk whole numbers are integers that are 0 and greater so its 0,1,2,3,4,5 ......
So which equations when you subtract do you NOT get a whole number or rather do you get a negative number?
a and c
Ok so A and C we subtracted and still have a whole number or rather we still have a positive number We wanna find an equation where we subtract 2 whole numbers and end up with a negative integer Additionally If you take a look in Option A we have 1 – (–2) = 3 And -2 is a negative integer and hence not even a whole number
so a and c is the correct answer
ughhh Nope cuz its still a positive integer
Ok lemme try to explain again
so b and d
yes lol
Which sets of numbers are closed under addition? Choose all answers that are correct. A. {0, 2, 5, 8} B. even integers C. rational numbers D. {0}
can someone help me with this one
okkk ummm I gotta run soon but i want you to attempt to solve it on your own
So closed under addition means If you added the values in each set then you still will get a value within that set So lets take the set {0} If you add 0+0=0 Since 0 is in the set then we can conclude that the set {0} is closed under addition
i think it is a d and b
Lets look at the set " all even integers" So an even number is represented by 2k where k is an integer so for instance when k=1 we have 2*1=2 When k=2 we have 2*2=4 so basically 2k represents all even functions so 2k+2k=4k=2(2k) so we can conclude that all even integers are closed under addition
am I corrrect about a d and b
yes I am
ok good
Ok so I dont have time to explain rational numbers cuz I am running out but a rational number is closed under addition
so its not a d and b
Lemme get @freckles to help you
@freckles it offfline
ok so basically a is the only one that isnt closed under addition The rest are
hello
is this the question you are looking at: "Which sets of numbers are closed under addition? Choose all answers that are correct. A. {0, 2, 5, 8} B. even integers C. rational numbers D. {0}"
A) we can look at all the possibilities or we can try to find a counterexample to it being closed...(you know something showing that it is not false) or let's look at all the possibilities when you add any of the following, do you get a number inside the set {0,2,5,8} always: 0+0=? 0+2=? 0+5=? 0+8=? 2+2=? 2+0=? 2+5=? 2+8=? 5+0=? 5+2=? 5+5=? 5+8=? 8+0=? 8+2=? 8+5=? 8+8=? as soon as you run into a sum that is not an element of {0,2,5,8} you know the set {0,2,5,8} will not be closed under addition so what do you think about {0,2,5,8} closed or not closed under addition?
i think the answer is even integers and rational numbers
what about the set just containing 0 0+0 's sum is an element of {0} is it not?
or it could be just a
why do you think a?
so it is b and c
think about the sums I mentioned above for example is 2+8 an element {0,2,5,8}
no
so A is definitely not closed under addition
let's think about the even integers 2a is even for any integer a 2i is even for any integer i what about the sum of 2a and 2i 2a+2i=2(a+i) what does this say a bout the set of even integers under addition ?
yes
yes the set of even integers is totally closed under addition
now let's move on to the rationals m/n and c/b are elements of the rationals (Assuming of course n and b are not zero you know since we can not divide by 0 and also m,n,c,b are integers ) so what happens when we add m/n and c/b
\[\frac{m}{n}+\frac{c}{b}=\frac{m}{n} \cdot \frac{b}{b}+\frac{c}{b} \cdot \frac{n}{n}=\frac{mb+cn}{nb}\]
if m,n,c,b are integers then is mb+cn an integer?
I will give you a hint the set of integers is closed under addition and multiplication
so it is c and d
or b and c
I thought you agreed with me that the set of even integers was closed under addition we are now talking about the rationals an element of the rationals looks like m/n or you can say c/b where m,n,c,b are integers (and n and b are not 0) we are adding m/n and c/b to see if the set of rationals is closed under addition the rationals are numbers that can be written as a fraction where the numerator and denominator (not 0) are integer numbers
that is why I asked you to tell me if the sum of m/n and c/b 's numerator was an integer then I was going to ask about the denominator
\[\frac{m}{n}+\frac{c}{b}=\frac{mb+cn}{nb}\] I gave you the hint that the set of integers is closed under addition and multiplication which means both mb+cn and nb are integers which means m/n+c/b is an element of the rationals which means the set of rationals is closed under addition
and we already discussed the last choice {0} 0+0 is definitely an element of {0}
so b and c are correct or is it b and d
I'm confused. Which of my explanations are you having trouble with?
And why do you assume you have only 2 choices of the 4 that are correct
again 2a+2i=2(a+i) which is still an even number and m/n+c/b=(mb+nc)/nb where both mb+nc and nb are integers (where nb is not zero) so m/n+c/b is still rational 0+0 is an element of 0 and finally 2+8 is not an element of {0,2,5,8}
is an element of {0}
so it it is b c and d
yes do you understand why ?
if not can you please tell me which of my explanations doesn't make sense?
yes
Numbers p and q are negative integers. Which statements are always true? Choose all answers that are correct. A. p + q is a negative integer B. p • q is a positive integer C. p – q is a negative integer D. is a negative integer
i think this one is a and c
so a negative number times a negative number isn't positive ?
also what is -5-(-5)?
and I can't tell what D is
so is it a and c
yep its a and c
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