Question

What is the remainder when

Answer 1

\[x^4-2x^2+4x^2-3\]

Answer 2

divided by (x+2)

Answer 3

Answers :-27 5 13 45

Answer 4

@jim_thompson5910

Answer 5

@jdoe0001

Answer 6

use synthetic division, should be simple enough I'd think \(\large {
x^4-2x^2+4x^2-3 \div x+2\implies x^4-2x^2+4x^2+{\color{brown}{ 0x}}-3 \div x+2
\\ \quad \\

\begin{array}{lllllll}
-2&|&1&-2&4&0&-3\\
&|&\\
\\\hline\\
&&1
\end{array}
}\)

Answer 7

the remainder theorem

Answer 8

ohhh hemmm

Answer 9

ok so.... well
recall that the remainder theorem says that

f(x) divided by (x-a) gives a remainder of f(a)

Answer 10

f(1)=1^4-2(1)^2+4(1)^2 - 3

Answer 11

=

Answer 12

1+2+4-3=

Answer 13

\(\bf f(x)=x^4-2x^2+4x^2-3
\\ \quad \\
\cfrac{f(x)}{x+2}\implies \cfrac{f(x)}{x-({\color{brown}{ -2 }})}
\\ \quad \\
f(x)\textit{ remainder will then be }=f({\color{brown}{ a}})\)

Answer 14

so what do I plug in?

Answer 15

:/

Answer 16

plug in "a" from the form (x-a)

in this case a = -2
notice above

(x+2) will be (x - ( -2))

Answer 17

https://www.wolframalpha.com/input/?i=%28x%5E4-2x%5E2%2B4x%5E2-3%29%28x-%28-2%29

Answer 18

well it is synthetic division then apply remainder theorem

Answer 19

I got -27