0.5000 kg of water at 35.00 degrees Celsius is cooled, with the removal of 6.300 E4 J of heat. What is the final temperature of the water? Specific heat capacity of water is 4186 J/(kg Co). Remember to identity all of your data, write the equation, and show your work.

Question

anonymous · Answer

and also How would you explain the concept of an expanding universe to a fellow scientist?

anonymous · Answer

I would greatly appreciate some help!!! Thank you!!!!! Medals will be awarded!

matt101 · Answer

You can solve this question using the following equation:

$$q=mc \Delta T$$
Where q is the total heat absorbed/released, m is the mass, c is the specific heat, and ΔT is the change in temperature.

shamim · Answer

The above equation is right !!!!!

shamim · Answer

Given
q=6.3*E4 joules
c=4186j/kg/c
Theta1=35degree celcius
Theta2=?

shamim · Answer

We can rewrite the above equation as
q=mc*(theta1-theta2)
Theta2=?