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Mathematics 15 Online
OpenStudy (anonymous):

help on a limit problem?

OpenStudy (anonymous):

\[\lim \rightarrow \infty \cos ( \frac{ 5x }{ x^2+7 } +\frac{ \pi }{ 3 })\]

myininaya (myininaya):

do you know the following equals: \[\lim_{x \rightarrow \infty} \frac{5x}{x^2-7}\]

myininaya (myininaya):

and whatever -7 or +7 either way this limit is?

OpenStudy (anonymous):

is the limit to that 0??

myininaya (myininaya):

yes the particular limit I asked about is 0 \[\lim_{x \rightarrow \infty}\cos(\frac{5x}{x^2+7}+\frac{\pi}{3} ) \\ =\lim_{u \rightarrow 0}\cos(u+\frac{\pi}{3})\]

myininaya (myininaya):

do you know how to evaluate your limit now?

OpenStudy (anonymous):

so is that 1?

myininaya (myininaya):

well you can find that limit by direct substitution now

myininaya (myininaya):

cos(0+pi/3) is that 1?

OpenStudy (anonymous):

no thats 1/2 ...

myininaya (myininaya):

yep :)

OpenStudy (anonymous):

wow thank you so much!

myininaya (myininaya):

np

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