Question

Can someone explain how I write this? 3(Ba+2 & 2 OH-)(aq) + 2(3H+ & PO4-3)(aq)
-->1Ba3(PO4)2 (s) & 6 H2O (l)

Answer 1

how you write what exactly?

Answer 2

3(Ba+2 & 2 OH-)(aq) I don't really understand what this means. How it should be written out on paper for example.

Answer 3

\(\huge 3~Ba^{2+}_{(aq)} + 2~ OH^-_{(aq)}\)

Answer 4

Okay. So the 3 is only for the Ba then

Answer 5

What about this part 2(3H+ & PO4-3)(aq) ?

Answer 6

oh wait, no in that case it would be \(6 ~OH^−_{(aq)}\), the 3 needs to be distributed to the hydroxide to balance the charges

Answer 7

Is it the same for the Ba and OH?

Answer 8

\(\huge 6H^+ + 2PO_4^{-3} \)

Answer 9

Ba would be 3 and hydroxide 6

Ba is 2+ times 3 is +6

OH is -1, times 6 is -6

so charges are balalnced

Answer 10

Thank you

Answer 11

no problem

Answer 12

Sorry. Could you write out the full thing? I keep doing something wrong.