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OpenStudy (anonymous):

Can someone write out the ionic equation for Ba(OH)2 (aq) + H3PO4(aq) --> so I can check my work, please?

OpenStudy (australopithecus):

just post it I will let you know

OpenStudy (australopithecus):

http://www.occc.edu/kmbailey/Chem1115Tutorials/Net_Ionic_Eqns.htm This should help as well

OpenStudy (anonymous):

3Ba^+_2 (aq) +2OH^- (aq) + 6H^+ (aq) +PO_4^3- (aq) --> Ba_3(PO_4)_2 (s) + 6H_2O (l)

OpenStudy (anonymous):

Sorry for the late reply.

OpenStudy (chmvijay):

its right :)

OpenStudy (anonymous):

Thank you

OpenStudy (anonymous):

The program keeps counting it wrong for some reason. Any ideas?

OpenStudy (anonymous):

Ba2+ (aq) + 2 OH- (aq) + H3PO4 (aq) -> 2 H2O (l) + Ba2+ (aq) + HPO4 2- (aq)

OpenStudy (anonymous):

Someone said that was right

OpenStudy (chmvijay):

if 3Ba^+2 then u should have 6 OH^- ions

OpenStudy (anonymous):

True. That was what I was thinking

OpenStudy (chmvijay):

and 6 H+ and 6 OH_ is equal to 6H2O

OpenStudy (anonymous):

The program has just been refusing to take my answer so I'm thinking I'm wrong.

OpenStudy (anonymous):

True

OpenStudy (chmvijay):

yaa you were wrong

OpenStudy (chmvijay):

u got now ?

OpenStudy (anonymous):

Could you write it out so I can double check? Sorry

OpenStudy (chmvijay):

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