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OpenStudy (anonymous):
Can someone write out the ionic equation for Ba(OH)2 (aq) + H3PO4(aq) --> so I can check my work, please?
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OpenStudy (australopithecus):
just post it I will let you know
OpenStudy (anonymous):
3Ba^+_2 (aq) +2OH^- (aq) + 6H^+ (aq) +PO_4^3- (aq) --> Ba_3(PO_4)_2 (s) + 6H_2O (l)
OpenStudy (anonymous):
Sorry for the late reply.
OpenStudy (chmvijay):
its right :)
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OpenStudy (anonymous):
Thank you
OpenStudy (anonymous):
The program keeps counting it wrong for some reason. Any ideas?
OpenStudy (anonymous):
Ba2+ (aq) + 2 OH- (aq) + H3PO4 (aq)
-> 2 H2O (l) + Ba2+ (aq) + HPO4 2- (aq)
OpenStudy (anonymous):
Someone said that was right
OpenStudy (chmvijay):
if 3Ba^+2 then u should have 6 OH^- ions
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OpenStudy (anonymous):
True. That was what I was thinking
OpenStudy (chmvijay):
and 6 H+ and 6 OH_ is equal to 6H2O
OpenStudy (anonymous):
The program has just been refusing to take my answer so I'm thinking I'm wrong.
OpenStudy (anonymous):
True
OpenStudy (chmvijay):
yaa you were wrong
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OpenStudy (chmvijay):
u got now ?
OpenStudy (anonymous):
Could you write it out so I can double check? Sorry
OpenStudy (chmvijay):
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