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Mathematics 5 Online
OpenStudy (anonymous):

(2)/(y+2) + (3)/(y) = (-y)/ (y+2)

OpenStudy (fibonaccichick666):

so, what do we need to add fractions?

OpenStudy (anonymous):

it says to solve the equation

OpenStudy (fibonaccichick666):

right, and in order to do so, you need to add those fractions together

OpenStudy (fibonaccichick666):

So, what do you need to add fractions?

OpenStudy (anonymous):

find y?

OpenStudy (fibonaccichick666):

ah, no, like if you had \[\frac{1}{3}+\frac{1}{2}\] what would you need to do first?

OpenStudy (anonymous):

find the bottom which is 6

OpenStudy (anonymous):

1/3 +1/2= 5/6

OpenStudy (fibonaccichick666):

right, so you found the least common denominator. We need to do that here too

OpenStudy (fibonaccichick666):

if we find that, then we can multiply both sides of our equation by it and have no fractions to deal with

OpenStudy (anonymous):

ok

OpenStudy (fibonaccichick666):

So, we need the least common multiple of \(y,~(y+2), ~and~(y+2)\) Can you tell me what that is?

OpenStudy (anonymous):

y^2+4y+4

OpenStudy (fibonaccichick666):

So that is \((y+2)^2\), does y divide every term there?

OpenStudy (anonymous):

yes?

OpenStudy (fibonaccichick666):

Does 4 divide evenly by y?

OpenStudy (anonymous):

yeah?

OpenStudy (fibonaccichick666):

No, it does not. 4y divides by y, we get 4. But 4/y can't be divided evenly

OpenStudy (fibonaccichick666):

So we need something that can be divided by both y and (y+2)

OpenStudy (fibonaccichick666):

give it another go

OpenStudy (anonymous):

oh ok i see

OpenStudy (fibonaccichick666):

Think about the numeric example, how did you get 6?

OpenStudy (anonymous):

multiply

OpenStudy (fibonaccichick666):

**Hint** **Hint***

OpenStudy (fibonaccichick666):

So, what is the least common multiple we need here?

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