Mathematics
5 Online
OpenStudy (anonymous):
(2)/(y+2) + (3)/(y) = (-y)/ (y+2)
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OpenStudy (fibonaccichick666):
so, what do we need to add fractions?
OpenStudy (anonymous):
it says to solve the equation
OpenStudy (fibonaccichick666):
right, and in order to do so, you need to add those fractions together
OpenStudy (fibonaccichick666):
So, what do you need to add fractions?
OpenStudy (anonymous):
find y?
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OpenStudy (fibonaccichick666):
ah, no, like if you had \[\frac{1}{3}+\frac{1}{2}\] what would you need to do first?
OpenStudy (anonymous):
find the bottom which is 6
OpenStudy (anonymous):
1/3 +1/2= 5/6
OpenStudy (fibonaccichick666):
right, so you found the least common denominator. We need to do that here too
OpenStudy (fibonaccichick666):
if we find that, then we can multiply both sides of our equation by it and have no fractions to deal with
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OpenStudy (anonymous):
ok
OpenStudy (fibonaccichick666):
So, we need the least common multiple of \(y,~(y+2), ~and~(y+2)\) Can you tell me what that is?
OpenStudy (anonymous):
y^2+4y+4
OpenStudy (fibonaccichick666):
So that is \((y+2)^2\), does y divide every term there?
OpenStudy (anonymous):
yes?
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OpenStudy (fibonaccichick666):
Does 4 divide evenly by y?
OpenStudy (anonymous):
yeah?
OpenStudy (fibonaccichick666):
No, it does not. 4y divides by y, we get 4. But 4/y can't be divided evenly
OpenStudy (fibonaccichick666):
So we need something that can be divided by both y and (y+2)
OpenStudy (fibonaccichick666):
give it another go
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OpenStudy (anonymous):
oh ok i see
OpenStudy (fibonaccichick666):
Think about the numeric example, how did you get 6?
OpenStudy (anonymous):
multiply
OpenStudy (fibonaccichick666):
**Hint** **Hint***
OpenStudy (fibonaccichick666):
So, what is the least common multiple we need here?