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Mathematics 21 Online
OpenStudy (ayyookyndall):

Hep Needed!

OpenStudy (isaiah.feynman):

This is a multi step problem.

OpenStudy (ayyookyndall):

Whats first?

iYuko (iyuko):

Use Pythagorean theorem

iYuko (iyuko):

\[b ^{2}*c ^{2}=a ^{2}\] Because wwe are trying to find the lst side.

iYuko (iyuko):

Sorry +

iYuko (iyuko):

Beg to differ.

JoelTheBoss (joel_the_boss):

The slant height is the hypotenuse of a right triangle formed between a point midway along an edge of the pyramid, the top of it, and a point directly below the top of the pyramid.

OpenStudy (ayyookyndall):

32^2 + 34^2 = a^2 1024 + 1156 = 2180 So the answer is 46.7?

iYuko (iyuko):

The volume of a pyramid is 1/3 the area of the base times the vertical height.

OpenStudy (anonymous):

height is missing though

iYuko (iyuko):

The vertical is not given so we use Pythagorean theorem

OpenStudy (ayyookyndall):

Here are the answer choices a. 30,720 cm^2 b. 15,360 cm^2 c. 11, 605 cm^2 d. 10,240 cm^2

OpenStudy (isaiah.feynman):

Okay, the volume of the pyramid id the area of the square base multiplied by the STRAIGHT height of the pyramid. We need to find the STRAIGHT height.

OpenStudy (isaiah.feynman):

We need the theorem actually.

iYuko (iyuko):

So use the equation i told then solve for a

iYuko (iyuko):

A =??

JoelTheBoss (joel_the_boss):

One side of this right triangle is the height of the pyramid, \(32~cm\). The other is a line from the center of a side to the center of the square. This will be \(\frac{1}{2}\) of the length of a side or \(17~cm\).

OpenStudy (ayyookyndall):

So whats next?

iYuko (iyuko):

@ayyookyndall said 46.7 So now... 46.7(32^2/3)

OpenStudy (isaiah.feynman):

iYuko (iyuko):

What is \[32^{2}\]

OpenStudy (ayyookyndall):

1024

OpenStudy (isaiah.feynman):

Okay, I'm leaving. Too many hands in the pot.

iYuko (iyuko):

\[46.7(1024/3)\]

iYuko (iyuko):

What is 1024/3?

OpenStudy (adi3):

wht the hell is this [Math Processing Error]

OpenStudy (adi3):

why does it come every time @iYuko

iYuko (iyuko):

@ayyookyndall 1024/3

JoelTheBoss (joel_the_boss):

Hypotenuse=\(\sqrt{34^2+17^2}=\)

OpenStudy (ayyookyndall):

@iYuko 341.3

OpenStudy (adi3):

@Joel_the_boss u r saying Hypotenuse=[Math Processing Error]

iYuko (iyuko):

46.7*341.3

OpenStudy (ayyookyndall):

1445 @Joel_the_boss

OpenStudy (ayyookyndall):

15938.71 @iYuko

OpenStudy (adi3):

@Joel_the_boss answer my question first

iYuko (iyuko):

I messed up.....

iYuko (iyuko):

Hmmmm... let me go look back.

OpenStudy (ayyookyndall):

So whats next?

iYuko (iyuko):

I'm not sure that was supposed to be the answer.

iYuko (iyuko):

But it was wrong.

OpenStudy (ayyookyndall):

I believe its D

OpenStudy (ayyookyndall):

@dtan5457 @Joel_the_boss

JoelTheBoss (joel_the_boss):

@ayyookyndall Ok not 34 I meant 32. \[\sqrt{32^2+17^2}=?\] do exponents and not the addition. that way we can continue the next step.

OpenStudy (ayyookyndall):

1024 + 289

JoelTheBoss (joel_the_boss):

\(\sqrt{1024+289}=1313\) \(\sqrt{1313}=?\) Ok now we can square root so what did you get? :)

OpenStudy (ayyookyndall):

36.235

OpenStudy (ayyookyndall):

Whats next?

JoelTheBoss (joel_the_boss):

Well that's akward I solved it LOL What exactly were you looking for? I thought you wanted me to solve ;)

OpenStudy (ayyookyndall):

Well was the answer you got one of the answer choices?

OpenStudy (ayyookyndall):

@Joel_the_boss ??

JoelTheBoss (joel_the_boss):

Ok @iYuko We need to work together because were both lost @thomaster What did we do wrong.. ;-;

iYuko (iyuko):

Yea, but I have no clue what I did wrong.

JoelTheBoss (joel_the_boss):

http://www.calculatorsoup.com/calculators/geometry-solids/pyramid.php Try this LOL Im not the best at geometry

iYuko (iyuko):

We have to use the Pythagorean theorem

iYuko (iyuko):

A calculator...LOL!!! They make a calculator for this!

OpenStudy (isaiah.feynman):

You don't use 32, you use half of 32. The triangle inside that pyramid consists of the slant height, HALF of the square's side and the straight height.

JoelTheBoss (joel_the_boss):

They have a calculator for everything XD

iYuko (iyuko):

V = 11605.3 cm3

OpenStudy (ayyookyndall):

So what would be the formula @Isaiah.Feynman

iYuko (iyuko):

#TheCalculator

iYuko (iyuko):

The calculator says V = 11605.3 cm3

OpenStudy (ayyookyndall):

Thats an option!!!

OpenStudy (isaiah.feynman):

What if that option is wrong? :P

JoelTheBoss (joel_the_boss):

Ehh, that's a DA, at least explain how you got it. :P

iYuko (iyuko):

@ayyookyndall We rounded 46.7 wrong Its supposed to be 40.8412

iYuko (iyuko):

That's y our answer was wrong

iYuko (iyuko):

Good enough @Joel_the_boss ? Or do I need to explain more?

iYuko (iyuko):

That's the reason our answer is wrong.

OpenStudy (adi3):

u still dint get the answer @ayyookyndall

OpenStudy (phi):

***What is the volume of a square pyramid with base edges of 32 cm and a slant height of 34 cm?**** To solve these problems, you should follow this process. 1. The first step is find the formula for the volume of a pyramid. You may have memorized it? or look in your notes, or google it. But find it. \[ V = \frac{1}{3} A h \] where A is the area of the base (bottom face of the pyramid) 2. Try to sketch the problem. This might be harder than step 1. But try |dw:1430307021547:dw|

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