The probabilities of different newspapers having an advertisement on the front page are given in the table. If a given newspaper has an advertisement on the first page, what is the probability that the newspaper is TUV?
a. 82.4%
b. 86.3%
c. 88.7%
d. insufficient data
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OpenStudy (anonymous):
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@Michele_Laino
OpenStudy (anonymous):
I am thinking it is insufficient data. C is not the right answer..
OpenStudy (anonymous):
@nincompoop
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OpenStudy (anonymous):
Is it D?
ganeshie8 (ganeshie8):
@Mimi_x3
OpenStudy (anonymous):
It was d
ganeshie8 (ganeshie8):
nice, it was very tricky haha!
OpenStudy (michele_laino):
I think that:
since we have 6 newspapers, the probability to get the TUV newspaper is 1/6, so the requested probability is given by the subsequent product of the single probabilities:
1/6*.887
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OpenStudy (michele_laino):
p=1/6* 0.887=14.78 %
OpenStudy (anonymous):
Yea, and since that answer was not there it is insufficient data.