Question

Physics- Help me Please

Answer 1

Using the conversion factor from eV (electron volts to Joules), determine which energy line for an electron dropping from one energy level to another would show a line at 435 nm in an emission spectrum.

Needed constants:
1.00eV=1.6*10^-19 J
c=3.00*10^8 m/s
h=6.63*10^-34 Js

Energy Level Values:
E6: E=-0.378 eV
E5: E=-0.544 eV
E4: E=-0.850 eV
E3: E=-1.51 eV
E2: E=-3.403 eV

Answer 2

Find the energy in joules with \(E_{photon}=\dfrac{hc}{\lambda}\)

convert the energy from J to eV

Answer 3

Okay and what would the wavelength be?

6.63*10^-34*3.00*10^8/ wavelength?

Answer 4

@aaronq

Answer 5

435 nm (needs to be in meters)

Answer 6

4.35*10^-7?

So 6.63*10^-34*3.00*10^8/4.35*10^-7?

@aaronq

Answer 7

yup

Answer 8

Is it 4.57*10^-33?? I got that for an answer?

Answer 9

@aaronq