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Physics- Help me Please
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Using the conversion factor from eV (electron volts to Joules), determine which energy line for an electron dropping from one energy level to another would show a line at 435 nm in an emission spectrum. Needed constants: 1.00eV=1.6*10^-19 J c=3.00*10^8 m/s h=6.63*10^-34 Js Energy Level Values: E6: E=-0.378 eV E5: E=-0.544 eV E4: E=-0.850 eV E3: E=-1.51 eV E2: E=-3.403 eV
Find the energy in joules with \(E_{photon}=\dfrac{hc}{\lambda}\) convert the energy from J to eV
Okay and what would the wavelength be? 6.63*10^-34*3.00*10^8/ wavelength?
@aaronq
435 nm (needs to be in meters)
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4.35*10^-7? So 6.63*10^-34*3.00*10^8/4.35*10^-7? @aaronq
yup
Is it 4.57*10^-33?? I got that for an answer?
@aaronq
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