OpenStudy (anonymous):

ln(x^3y^4z^5)

3 years ago
OpenStudy (anonymous):

in fully expanded form

3 years ago
OpenStudy (anonymous):

In x^3 +In y^4 + In z^5

3 years ago
OpenStudy (anonymous):

3In x +4In y +5In z

3 years ago
OpenStudy (anonymous):

3In x-4In y -5In z

3 years ago
OpenStudy (anonymous):

60 In xyz

3 years ago
OpenStudy (anonymous):

this deals with logarithms I guess

3 years ago
OpenStudy (amorfide):

\[\ln(a)+\ln(b)=\ln(a \times b)\] and obviously you can split it up if you start with \[\ln(a \times b)=\ln(a)+\ln(b)\]

3 years ago
OpenStudy (amorfide):

so in your logarithm, you have the product of 3 terms, therefore you know that you are adding 3 logarithms

3 years ago
OpenStudy (amorfide):

so you can split them up

3 years ago
OpenStudy (amorfide):

\[\ln(a \times b \times c)=\ln(a)+\ln(b)+\ln(c)\] this is what you start with and what you will end up with

3 years ago
OpenStudy (anonymous):

so the answer is a

3 years ago
OpenStudy (anonymous):

so the answer is D

3 years ago
OpenStudy (amorfide):

a is correct, but it is not fully expanded now we use another rule

3 years ago
OpenStudy (anonymous):

or b

3 years ago
OpenStudy (amorfide):

\[\ln(a)^{b}= bln(a)\]

3 years ago
OpenStudy (amorfide):

so yes b is correct

3 years ago