OpenStudy (anonymous):

ln(x^3y^4z^5)

2 years ago
OpenStudy (anonymous):

in fully expanded form

2 years ago
OpenStudy (anonymous):

In x^3 +In y^4 + In z^5

2 years ago
OpenStudy (anonymous):

3In x +4In y +5In z

2 years ago
OpenStudy (anonymous):

3In x-4In y -5In z

2 years ago
OpenStudy (anonymous):

60 In xyz

2 years ago
OpenStudy (anonymous):

this deals with logarithms I guess

2 years ago
OpenStudy (amorfide):

\[\ln(a)+\ln(b)=\ln(a \times b)\] and obviously you can split it up if you start with \[\ln(a \times b)=\ln(a)+\ln(b)\]

2 years ago
OpenStudy (amorfide):

so in your logarithm, you have the product of 3 terms, therefore you know that you are adding 3 logarithms

2 years ago
OpenStudy (amorfide):

so you can split them up

2 years ago
OpenStudy (amorfide):

\[\ln(a \times b \times c)=\ln(a)+\ln(b)+\ln(c)\] this is what you start with and what you will end up with

2 years ago
OpenStudy (anonymous):

so the answer is a

2 years ago
OpenStudy (anonymous):

so the answer is D

2 years ago
OpenStudy (amorfide):

a is correct, but it is not fully expanded now we use another rule

2 years ago
OpenStudy (anonymous):

or b

2 years ago
OpenStudy (amorfide):

\[\ln(a)^{b}= bln(a)\]

2 years ago
OpenStudy (amorfide):

so yes b is correct

2 years ago
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