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ln(x^3y^4z^5)
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in fully expanded form
In x^3 +In y^4 + In z^5
3In x +4In y +5In z
3In x-4In y -5In z
60 In xyz
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this deals with logarithms I guess
\[\ln(a)+\ln(b)=\ln(a \times b)\] and obviously you can split it up if you start with \[\ln(a \times b)=\ln(a)+\ln(b)\]
so in your logarithm, you have the product of 3 terms, therefore you know that you are adding 3 logarithms
so you can split them up
\[\ln(a \times b \times c)=\ln(a)+\ln(b)+\ln(c)\] this is what you start with and what you will end up with
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so the answer is a
so the answer is D
a is correct, but it is not fully expanded now we use another rule
or b
\[\ln(a)^{b}= bln(a)\]
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so yes b is correct
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